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I saw byte code for `val variable = 90` and in the decompiled bytecode it produced `int variable = true;`. I don't understand this ?

~Looks like a compiler optimization. You're probably not using the value~

~Yup, seems to be the case, as soon as you use the value, e.g. `println(variable)` it becomes `90` again.~

Well the `90` is in the bytecode, so it's not actually optimized away.

This is a decompiler :shrug: 
It may be buggy, especially with Kotlin, if it's easy to reproduce you can report on Kotlin issue tracker

He could be using those standard functions.