If you are in a function in a supertype and have a...

# announcements

[Kroppeb]

If you are in a function in a supertype and have a variable that is of that type but then smartcasted to a subtype, why do the private functions of the supertype get hidden?

[Kroppeb]

atm I'm getting around it by casting it back to the supertype, but I feel like I shouldn't need to.

[karelpeeters]

Can you give us a minimal example?

[Evan R.]

If a class member is private, that means child class instances are unable to access that member. Smart-casting causes Kotlin to treat the variable as a subtype. If you want this behavior, consider making the class member in question protected rather than private or just keep performing the supertype cast.

[Kroppeb]

It's annoying if you were to refactor a part earlier in the code which results in a smartcast and creates and error later in said function