java.lang.Long.parseLong()

Why isn't this available in the Kotlin

Long

?

Because "5".toLong() does the job

Thank you 😄

🙂

But what about

parseUnsignedLong()

? (I am parsing a binary data stream so I need to differentiate). There is a

.toULong()

but it actually returns an

ULong

which I don't want to use because it's marked as experimental. The Java

parseUnsignedLong()

returns a normal

Long

. I guess I either have to use

ULong

or use the Java method.

Still makes Idea shout at me for using experimental types but makes my function return the correct type so it will do. Thank you.

Mind that a large ULong does not fit inside a Long. (Since it goes further into positive number ranges which it does not need to go into the negative) So if you do that it is maybe just enough to do toLong() and check if number is positive.

For numbers larger than Long.MAX_VALUE, they get wrapped around, so ULong.MAX_VALUE == -1 (Long)

Yes I parse a string of binary (with radix = 2), checking the number of bits beforehand against

Long.SIZE_BYTES

. Seems to work so far.