``` class Env { fun sub() = SubEnv(this) } cl...

# announcements

[karelpeeters]

class Env {
    fun sub() = SubEnv(this)
}

class SubEnv(val parent: Env)

Is there a nice way to make sub() the only possible way to construct a SubEnv instance? Making the constructor of SubEnv private isn't allowed. Making SubEnv an inner class doesn't help either, you're still not allowed to make the constructor private.

[spand]

Make SubEnv an interface or sealed baseclass and make SubEnvImpl private

[karelpeeters]

Yeah I was afraid I'd have to do that 😕