What is the correct way to compare Byte to Int? `if (myByte.compareTo(myInt) == 0)`? `if (myByte.toI...

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[Robert]

What is the correct way to compare Byte to Int? if (myByte.compareTo(myInt) == 0)? if (myByte.toInt() == myInt)? if (myByte == myInt.toByte())? Something else? Or can I force implicit conversion somehow, as I have a lot of these comparisons?

[jlleitschuh]

if (myByte.toInt() == myInt) would be the most appropriate I think.

[Robert]

@jlleitschuh Cool. Is there any reasoning to it? Or is it personal preference?

[jlleitschuh]

if (myByte == myInt.toByte())
If there is an overflow in the int to byte conversion, you'll have weird behavior.

if (myByte.compareTo(myInt) == 0)
This is just confusing from a readability perspective and I don't even know if it will compile.

[hudsonb]

I definitely wouldn't narrow the `Int`: if (myByte == myInt.toByte()). 123456.toByte() is 64.

[Robert]

Okay, thanks, then I'll go with the myByte.toInt()