I m getting around it using `serializeRef it as RefHolder lt kotlinlang #announcements

I'm getting around it using `serializeRef(it as Re...

Ruckus

12/21/2018, 10:56 PM

I'm getting around it using

serializeRef(it as RefHolder<Nothing>, ...)

which works due to erasure, but it feels wrong and dirty.

Andreas Sinz

12/22/2018, 9:13 AM

Does

source.refs

contain `Ref`s with the same or different`T`s?

Ruckus

12/22/2018, 3:01 PM

Different, thus the need for

<*>