hi there, what is the best way to solve that problem?:

open class ParentFoo
class ChildFoo : ParentFoo()

abstract class ParentBar {
	open var foo: ParentFoo? = null
}
class ChildBar : ParentBar() {
	override var foo: ChildFoo?
		get() = super.foo as ChildFoo?
		set(value) {
			super.foo = value
		}
}

right now I'm not allowed to set

ChildFoo

as the `ChildBar`'s

foo

property type as it is not exactly the same type as its parent's

foo

, but as it doesn't have a backing field I think this should be able to compile without any problem. What am I missing there?

If it is expected that

ChildBar

should contain only

ChildFoo

in

foo

, then I would have an

abstract val foo

in `ParentBar`:

open class ParentFoo
class ChildFoo : ParentFoo()

abstract class ParentBar {
    abstract val foo: ParentFoo?
}

class ChildBar : ParentBar() {
    override var foo: ChildFoo? = null
}

That way you will be able to get

ParentFoo

from

ParentBar

and get and set

ChildFoo

from

ChildBar

.

Thank you, sorry for the late response