Nikky
09/02/2018, 10:13 PMprintln { "" }
prints: () -> kotlin.String
is that because println accepts Any so i can pass it a KFunction<String> ?
i think there should be a println overload that takes () -> Any
and passes it to the normal println after executingnwh
09/02/2018, 10:15 PMnwh
09/02/2018, 10:16 PM