`val <K, V>SortedMap<K, V>.first get()...
# announcementse
elect
07/25/2018, 9:24 AMval <K, V>SortedMap<K, V>.first get() =...d
diesieben07
07/25/2018, 9:24 AMWorks for me...
e
elect
07/25/2018, 9:26 AMuhm, me too
elect
07/25/2018, 9:26 AMI must have wrote something nasty previously
k
karelpeeters
07/25/2018, 9:29 AMSomething like
val <T> T.foo get() = ...d
diesieben07
07/25/2018, 9:29 AMYes, it does.
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k
karelpeeters
07/25/2018, 9:31 AMWhat? I remeber there being a compiler error on something like this.
g
gildor
07/25/2018, 9:31 AMNo, it’s completely valid code
o
orangy
07/25/2018, 10:59 AM
The (simplified) rule AFAIR is that all type parameters should be mentioned in the receiver type. Can’t do something like
val <T, R> T.prop : R …👍 4
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