What would be the right way to generate an UUID in kotlin?

# announcements

[Alin B.]

What would be the right way to generate an UUID in kotlin?

[Andreas Sinz]

UUID.randomUUID()

[Alin B.]

I used that but it uses java.util. I thought there is something built in. Thank you

[Andreas Sinz]

Rule of thumb is, that kotlin reuses everything from java where its applicable and only adds stuff on top of it where its needed

[gildor]

It’s philosophy of Kotlin: Reuse everything what is available on the platform and add more idiomatic API for that if it’s required.
Allows to have small stdlib and close to zero overhead

[Alin B.]

So in this case, if I want to use this around my code, is it ok to have a file Utils in which have

`fun getUUID(): String {
    return UUID.randomUUID().toString()
}`

[gildor]

Sure

[Alin B.]

I am learning Kotlin and don't want to pass unneeded behavior from java

[gildor]

but I would rename it to something like randomUUID() or randomUUIDString()

[gildor]

Why? 🙂

[gildor]

Would it be something differrent if kotlin would provide
kotlin.util.UUID class?
The only difference practically would be just diffrent import, you now have jva.util.UUID

[gildor]

Good interop with platform is one of the strongest sides of Kotlin

[Alin B.]

I mean there are things done different in Kotlin and some things that are done in Java don't need to be made in Kotlin. For instance instead of StringUtils have fun directly in String.toUpperCase

[Andreas Sinz]

or even shorter fun getUUID() = UUID.randomUUID().toString()

[Can Orhan]

@Alin B. Yup! And that's a perfect example of reusing what the platform provides but making it more idiomatic

[gildor]

Exactly, Kotlin doesn’t have Utils classes, because you can use much more idiomatic and convenient extensions

[Alin B.]

Thank you to all for your time.