I can accomplish this with star types, but I'd rather have the type safety (and also the intellij help from knowing the type)

Why is

*

less safe in your example?

I can't really think of any reason it's less safe other than if the library I'm calling decides to change their signature, then my code will still compile (when it probably shouldn't)

*

just says I don't care what Generic Type the class has, I won't use it anyway, so if you actually not gonna use it, its safe to use

*

IMO

yeah, sounds good. I'll go with the

*

, but that means there is no way to grab the type of

this

and use it as the generic type? that kinda sucks. 😕

Well do you need to use it or not?

you can't use generic functions of

this

, yes

Can't you just add another generic type parameter that's not

reified

and isn't used?

@karelpeeters if you specify one parameter, you have to specify all of them. its either none or all

Huh that's too bad.

yeah 😞

Hi, is it valid to create an extension to the exception? something like this:

fun <T : Exception> T.expect(res: ResultValidator<A???>): ResultValidator<A???>

And then call like:

AccessDeniedException.expect(resultValidatorOfTypeBlah)

no, it's all a chain, so

expectException

is called on a chain of other methods.