Ruckus
05/11/2018, 8:53 PMany
and all
defined on Array<out T>
instead of Array<T>
?karelpeeters
05/11/2018, 9:27 PMRuckus
05/11/2018, 10:04 PMkarelpeeters
05/11/2018, 10:06 PMany
that isn't defined on Array<out T>
but on Array<T>
, but couldn't find a case where that didn't work exactly as the real one.Ruckus
05/11/2018, 10:07 PMArray<T>
and can't use any
because it's defined on Array<out T>
ilya.gorbunov
05/12/2018, 4:30 AMArray<T>
is a subtype of Array<out T>
, so any extensions for the latter are available for the former.Ruckus
05/12/2018, 4:50 AMkarelpeeters
05/12/2018, 6:25 AMout
then if its the same either way?Ruckus
05/12/2018, 3:02 PMkarelpeeters
05/12/2018, 3:51 PMilya.gorbunov
05/12/2018, 10:19 PMkarelpeeters
05/12/2018, 10:22 PMilya.gorbunov
05/12/2018, 10:30 PMT
position in a function signature.