Hi, could you please help me to find the succinct way of sorting two arrays? currently I have ``` v...

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[mike_shysh]

Hi, could you please help me to find the succinct way of sorting two arrays?
currently I have

val referenceServiceFeaturesConflicts = refResponse.serviceFeaturesConflicts
.sortedWith(compareBy({ it.addonPrecedence }, { it.sfName }))
val actualServiceFeatureConflicts = response.serviceFeaturesConflicts
.sortedWith(compareBy({ it.addonPrecedence }, { it.sfName }))

[Andreas Sinz]

why do you want to sort both arrays with a single line?

[mike_shysh]

just to make code prettier)

[spand]

I expect the most readable code would be to extract the comparator to a variable if thats possible

[spand]

Otherwise it seems pretty fine to me

[mike_shysh]

val sortByNameAndPrecedence: List<ServiceFeaturesConflicts>.() -> List<ServiceFeaturesConflicts> = {
            this.sortedWith(compareBy({ it.addonPrecedence }, { it.sfName }))
        }

[mike_shysh]

I made a lambda)

[spand]

So its now 5 lines in total ?

[nil2l]

Two arrays in single line:

listOf(v1, v2).map { it.sortedWith(yourLmbda) }

🤖

[mike_shysh]

I guesses there is some elegant solution=)

[nil2l]

Also lambda may do sort here, not just compare.

[mike_shysh]

@nil2l yeah, it's one of the possible ways

[mike_shysh]

thanks