<@U3DE1TXKP> any reason you need to specify the ty...

# announcements

[Andreas Sinz]

@robstoll any reason you need to specify the type?

[robstoll]

Unfortunately yes, I saw that it works if I do not have to

[czyzby]

You don't. This works for me:

fun main(args: Array<String>) {
    1 doStuff 1.2
}

infix fun <T> Int.doStuff(t: T) { println(t) }

[robstoll]

I am using it in a generic function, something like
fun <T> foo(a: T){ 1 test<T> a }

[robstoll]

ok, bad example as well 😄 let me check the usage

[robstoll]

my function is actually defined likes this:
infix inline fun <reified TSub : Any> IAssertionPlant<Any>.isA(noinline assertionCreator: IAssertionPlant<TSub>.() -> Unit)

[robstoll]

That's why I need to provide a type for TSub

[rkeazor]

can you put that into a code block in slack. its hard to read like that

[robstoll]

It is already in a code block, I'll put the parameter on a new line:

infix inline fun <reified TSub : Any> IAssertionPlant<Any>.isA( 
    noinline assertionCreator: IAssertionPlant<TSub>.() -> Unit
)

[rkeazor]

shouldn’t it be IAssertionPlant<Tsub>

[rkeazor]

?

[robstoll]

in case you mean IAssertionPlant<Any>, then nope isA is basically a down-cast assertion which allows you to tell that val a: Any = 1; assert(a).isA<Int>{} for instance