Why isn't it an error then?

# announcements

[karelpeeters]

Why isn't it an error then?

[diesieben07]

Because it can work if you know what you are doing, maybe. But yes, it's a bit strange.

[karelpeeters]

And it just doesn't inline it if it's not possible?

[diesieben07]

Well, in my example the compiler does not know that bar is to be inlined here, it just sees it as a normal virtual method and calls it. If the function relies on being inlined (e.g. using reified type parameters) things will blow up at runtime.

[dumptruckman]

Ah, good to know, thanks