evanchooly
07/06/2017, 12:08 PMsridhar
07/06/2017, 12:11 PMdiesieben07
07/06/2017, 12:12 PMdiesieben07
07/06/2017, 12:12 PMEugen Martynov
07/06/2017, 12:12 PMforEach
and reflection or if they are in array then just reference by indexevanchooly
07/06/2017, 12:12 PMsridhar
07/06/2017, 12:13 PMrobin
07/06/2017, 1:07 PMval (s1, s2, s3, s4, s5) = listOf(1, 2, 3, 4, 5).map { Node("q$it") }