If I have a function like `fun f(f1: () -> Unit = ::emptyOp, f2: () -> Unit = ::emptyOp)` and ...

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[alexp11223]

If I have a function like fun f(f1: () -> Unit = ::emptyOp, f2: () -> Unit = ::emptyOp) and I call it via f { } does it set the first or the last parameter?
I thought the first, but looks like it's the opposite?

[ilya.gorbunov]

alexp11223: lambda passed outside of parentheses always goes to the last parameter