hello everyone, does anyone knows how could i pars...

# android

[Lucca Beurmann]

hello everyone, does anyone knows how could i parse this date string: "2019-08-16 221646.919688+00" to a dd/mm/yyyy format?

[Remo]

this should help: https://developer.android.com/reference/java/text/SimpleDateFormat

[Lucca Beurmann]

I know i should a SimpleDateFormat(pattern).format(dateString)

[Lucca Beurmann]

But what should i use in the pattern parameter?

[Lucca Beurmann]

I'm trying this pattern:

[Lucca Beurmann]

yyyy-mm-dd H:m:s.z

[Tom Hermann]

lowercase ‘m’ is minute in hour.

The date part would be: yyyy-MM-dd
The time part would be: HH:mm:ss.SSSSSS
The time zone offset at the end is: X (assuming it is an iso8601 timezone offset 🤷)

So all together: yyyy-MM-dd HH:mm:ss.SSSSSSX

@Test
fun `convert sample date`() {
    val time = "2019-08-16 22:16:46.919688+00"
    val pattern = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss.SSSSSSX")

    val parsed = ZonedDateTime.parse(time, pattern)

    println(parsed)
}

[Harshit Singh]

You can take reference from this.

const val PATTERN_DATE_RECEIVED = "yyyy-MM-dd"
const val PATTERN_DATE_FORMATTED = "MM/dd/yyyy"
private fun getFormattedDate(dateTime: String?): String {
    val input = SimpleDateFormat(PATTERN_DATE_RECEIVED)
    val output = SimpleDateFormat(PATTERN_DATE_FORMATTED)
    try {
        return output.format(input.parse(dateTime?.substring(0, 10) ?: "") ?: "")
    } catch (e: ParseException) {
        e.printStackTrace()
    }
    return ""
}