Hi folks, I want to extract from an url the substring before `v[0..9]` e.g: ```<https://baseurl.tes...

# android

[Loredana Petrea]

Hi folks,

I want to extract from an url the substring before v[0..9]
e.g:

<https://baseurl.test/v1/example/{id}>

the result should be only <https://baseurl.test/>
Where the version number can be 1,2....9

Is there a way to do this?

[Tiago Nunes]

There is String.substringBefore, but it takes a specific String. For this I think you need to do:

Regex("v[0-9]").split(url).firstOrNull()

[Tiago Nunes]

Also, this would be better asked in #stdlib

[Vampire]

But splitting is a bit wasty if you use Regex anyway.
Better do it efficiently with a lookahead:

Regex("^.*?/(?=v[0-9]/)").find(url)?.value

[Loredana Petrea]

Thank you guys, the regex is what I missed 🙂