Hi, I have a doubt about Kotlin lazy property dele...

# android

[Jay]

Hi, I have a doubt about Kotlin lazy property delegation
For example, this property delegate with lazy: val x: String by lazy{...}
When I decompile the Kotlin code into Java code, I see that the getX() method is not ultimately called this method
public inline operator fun <T> Lazy<T>.getValue(thisRef: Any?, property: KProperty<*>): T = value
It is the getter method of value, which is getValue() instead of getValue(thisRef: Any?, property: KProperty<*>)
So, I don’t understand how the method getValue(thisRef: Any?, property: KProperty<*>) is called during the execution of lazy

[Jay]

image.png

[Jay]

val map2: MutableMap<String, Any?> = mutableMapOf("age" to "Jay", "name" to "18")
var age: Int? by map2



@Nullable
public final Integer getAge() {
   Map var1 = this.age$delegate;
   KProperty var3 = $$delegatedProperties[1];
   boolean var4 = false;
   return (Integer)MapsKt.getOrImplicitDefaultNullable(var1, var3.getName());
}

public final void setAge(@Nullable Integer var1) {
   Map var2 = this.age$delegate;
   KProperty var4 = $$delegatedProperties[1];
   boolean var5 = false;
   var2.put(var4.getName(), var1);
}

[Jay]

And Map delegation has the same confusion

[ephemient]

https://blog.jetbrains.com/kotlin/2019/12/what-to-expect-in-kotlin-1-4-and-beyond/ "Optimized delegated properties"

[Jay]

Thanks for the tip @ephemient