It creates a new list every time right? I forgot about `when` : ```destination.filterKeys { key -&gt...

# android

[Lilly]

It creates a new list every time right?
I forgot about when :

destination.filterKeys { key ->
    when (key) {
      in list1, list2, list3 -> true
      else -> false
    }
}

I'm fine with this, if no one else has a more convenient solution

[ephemient]

you mean in list1, in list2, in list3 -> right?

[ephemient]

it would be equivalent to key in list1 || key == list2 || key == list3 as you wrote it

[ephemient]

if you had a lot of lists, then maybe

listOf(list1, list2, list3).any { key in it }

would make sense. maybe not for just 3 of them, though

[Lilly]

it would be equivalent to key in list1 || key == list2 || key == list3 as you wrote it

if this is true, I made a mistake. Thanks for clarification @ephemient

[Vampire]

Yep, same error as Brians solution

[Vampire]

listOf(list1, list2, list3).all { key in it }

[Vampire]

Optimally with the listOf outside the lambda

[ephemient]

ah going back to previous conversation started in another thread, I see. yeah the when isn't going to do the right thing regardless

[ephemient]

depends on various factors, but creating an intersection set up front may be a good idea

[ephemient]

common = list1.toSet() intersect list2 intersect list3; key in common for example

[ephemient]

if you have more, it would be better to accumulate like
common = list1.toMutableSet()
common.retainAll(list2)
common.retainAll(list3)

[Lilly]

Thanks guys!