Hi, i start a picker with this code. i want to get the path for then read that file and send it to my backend with multipart using this line, in a xiaomi device works fine, there the path looks like this "/storage/emulated/0/Download/images.jpeg"

File(photoPath).asRequestBody("image/jpg".toMediaTypeOrNull())

//REQUEST_CODE_PICK_IMAGE = 101

Intent(Intent.ACTION_PICK).also {
    it.type = "*/*"
    val mimeTypes = arrayOf("image/jpeg", "image/png", "application/pdf")
    it.putExtra(Intent.EXTRA_MIME_TYPES, mimeTypes)
    startActivityForResult(it, REQUEST_CODE_PICK_IMAGE)
}

and then i use this

override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
    super.onActivityResult(requestCode, resultCode, data)
    if (resultCode == Activity.RESULT_OK) {
        when (requestCode) {
            REQUEST_CODE_PICK_IMAGE -> {
                selectedImageUri = data?.data
                Log.i("develop", "data: ... $data")
                image.setImageURI(selectedImageUri)
                homeViewModel.selectedImageUri = selectedImageUri?.lastPathSegment.toString()
            }
        }
    }
}

No, they cannot be converted. Content uris are relative to the package they refer to in the host segment and that package always brokers access to the content. The system gives you a temporary permission grant to access it, and you should open it with the ContentResolver when you get the activity result.

@Adam Powell so is there a way for opening that URI for getting this?

File(photoPath).asRequestBody("image/jpg".toMediaTypeOrNull())

No, use https://developer.android.com/reference/android/content/ContentResolver#openInputStream(android.net.Uri)