edwardwongtl
12/15/2017, 4:21 AMlist.map { it.id }
pablisco
12/15/2017, 9:27 AMinline fun <A, B> List<A>.mapBy(f: A.() -> B) =
this.map(f)
So you can use it like this:
list.mapBy { id }
But it's not standard so be careful 😄edwardwongtl
12/15/2017, 9:54 AM