```val invoke: suspend ()->Unit = fun(){} ``` S...

# getting-started

[smit01]

val invoke: suspend ()->Unit = fun(){}

Shows this error is it possible to declare suspending anonymous function with fun keyboard. I am also aware of suspending lambda that's not my question.
Thanks in advance.😇
error type mismatch: inferred type is () -> unit but suspend () -> unit was expected (line_27.kts132)

[Youssef Shoaib [MOD]]

suspend fun(){
    delay(10)
}

simply works