Hello everyone, just a small question. In kotlin lets say I do, `(10/3).toInt()` it returns 3 but wh...

# getting-started

[Ankit Shah]

Hello everyone, just a small question.
In kotlin lets say I do, (10/3).toInt() it returns 3 but what I want is the upper value i.e. 4. How can I achieve it?

[Igor Milakovic]

Perhaps do the ceil of 10/3 before toInt()?

[Ankit Shah]

Thanks @Igor Milakovic

[ruitzei]

Keep in mind that you’re performing an integer division and you’ll always get an int from that, one of the operands should be a double or a float to get that desired behaviour.

[elizarov]

If you want to round up integer division, then add denominator minus one to the nominator before division, e.g. (10 + 3 - 1) / 3

[ruitzei]

just make sure nominator + denominator doesn’t overflow 😂

[Diego Rodriguez]

you can avoid the overflow doing 1 + (nominator - 1) / denominator , e.g. 1 + (10 - 1) / 3

[mcpiroman]

Maybe there should be a std function - `assertEquals(4, 10 divUp 3)`I have defined it as a util in my project. Example impl:

infix fun Int.divUp(denominator: Int) = 1 + (this - 1) / denominator  // delegate handling of division by 0 to the / operator

might need special handling for nevative values though.