Trying to come up with a test function to assert that every member of a list is of a specified type This what I ve tried ```fun assertListTypes list List lt ParentType gt types List lt KType gt assertEquals list size types size types forEachIndexed idx type gt assert list idx is type assertListTypes list listOf typeOf lt Class1 gt typeOf lt Class2 gt ``` But the compiler didn t like the `is` check on the KType Any ideas

fun assertListTypes(list: List<ParentType>, types: List<KType>) {
    assertEquals(list.size, types.size)
    types.forEachIndexed { idx, type ->
        assert(list[idx] is type)
    }
}

assertListTypes(list, listOf(typeOf<Class1>(), typeOf<Class2>()))

But the compiler didn’t like the

is

check on the KType. Any ideas?

mkrussel

12/17/2021, 10:36 PM

is

checks can only be done with compile time constants on the right hand side. Instead you have to use reflection functions to determine if it is that type.

KClass.isInstance

could do that but I don't see anything on

KType

Miguel Vargas

12/17/2021, 10:40 PM

thanks, let me try with KClass

that worked!

like this

fun assertListTypes(list: List<ParentType>, types: List<KClass<*>>) {
    assertEquals(list.size, types.size)
    types.forEachIndexed { idx, type ->
        assert(type.isInstance(list[idx]))
    }
}
    
assertListTypes(list, listOf(Class1::class, Class2::class))

thanks for the help!

Daniel

12/19/2021, 2:36 PM

The requirement seems fishy. What would speak against equals asserting against a expected list?

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