Given: ```class Foo(val bar: Bar) class Bar(val baz: String) val foo = Foo(Bar("baz")) // why isn...

# getting-started

[dave08]

Given:

class Foo(val bar: Bar)
class Bar(val baz: String)


val foo = Foo(Bar("baz"))

// why isn't this possible?
val bazGetter = Foo::bar::baz

// whereas this is ok?
val bazGetter2: (Foo) -> String = { it.bar.baz }

[Joffrey]

Property references are not the same as lambdas technically. They can be more than just invoked, they are an actual description of the property. You can reference the property Bar::baz but not in the context of a particular Foo

[dave08]

Thanks for the explanation! I would have still expected that Foo::bar::baz would be the equivalent to Bar:baz as the description of the property the Foo:: being used just to traverse to it... but I guess that wouldn't make sense when the lambda interpretation is different...

[smit01]

class Foo(val name:String="none")
class Bar(val far:Foo = Foo())
((Bar::far)(Bar("smit"))::name)

[dave08]

That's a bit overkill (and I don't think it would work in my case...), I needed this for strikt's get(Foo::prop) function, to avoid get { it.bar.baz } which goes through the source files to get the name..., but thanks anyways!

[ephemient]

arrow lens also provides a way to compose getters, but if your use case requires a direct property reference then none of these will work