intervals = [[1,3],[2,6],[8,10],[15,18]]
Arrays.sort(intervals, compareBy { it[1] })

Hi guys, may i know how can i sort it in descending order based on the first index?

something like

val sorted = intervals.sortedDescendingBy{it.first()}

should do it

sortByDescending

to sort the current array,

sortedByDescending

to generate a list without affecting the original array

Thank you.

based on the first index

Note that

1

(as provided in the example) is not the first index, though. Using

it.first()

as suggested gives you index 0. Just keep this in mind when you choose what to pass to

sortedByDescending

.