```intervals = [[1,3],[2,6],[8,10],[15,18]] Arrays.sort(intervals, compareBy { it[1] })``` Hi guys, ...

# getting-started

[Ayden]

intervals = [[1,3],[2,6],[8,10],[15,18]]
Arrays.sort(intervals, compareBy { it[1] })

Hi guys, may i know how can i sort it in descending order based on the first index?

[Alex Prince]

something like val sorted = intervals.sortedDescendingBy{it.first()}
should do it

[Luke]

sortByDescending to sort the current array, sortedByDescending to generate a list without affecting the original array

[Ayden]

Thank you.

[Joffrey]

based on the first index

Note that 1 (as provided in the example) is not the first index, though. Using it.first() as suggested gives you index 0. Just keep this in mind when you choose what to pass to sortedByDescending .