Hey guys! I was quite surprised with this code: ```repeat(3) { if (it == 0) return@repeat prin...

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[evkaky]

Hey guys!
I was quite surprised with this code:

repeat(3) {
   if (it == 0) return@repeat
   println("inside repeat")
}

it prints “inside repeat” twice instead of 0 times
Why is that?

[ephemient]

repeat(3, block) ≈ block(0); block(1); block(2)

[ephemient]

your early return prevents println() when it == 0, but not 1 or 2

[evkaky]

Then is there any way to make a true break inside repeat or forEach (like we can do in regular loops)?

[ephemient]

as they're inline functions, you can return to an outer scope:

run {
    repeat(3) {
        if (it == 0) return@run
        println("inside repeat")
    }
}

but if that's necessary, IMO you should consider using a normal for loop instead.

for (i in 0 until 3) {
    if (i == 0) break
    println("inside for")
}