Jérémy CROS
09/02/2021, 9:45 AMlistOf(element0) + listOfElements + elementLast
But I’m not sure if there are more efficient / maybe clearer options available ?Javier
09/02/2021, 9:56 AMbuildList
val list = buildList {
add(element0)
addAll(elements)
add(elementLast)
}
val list = buildList {
add(index = 0, element = element0)
addAll(elements)
add(index = count(), element = elementLast)
}
That is more explicitKlitos Kyriacou
09/02/2021, 11:15 AMJérémy CROS
09/02/2021, 12:07 PMMichael Böiers
09/03/2021, 11:30 AMval listA = listOf("b", "c", "d")
val list = mutableListOf<String>().apply {
add("a")
addAll(listA)
add("e")
}