Steven Wang
09/24/2020, 1:33 PM`listOf("A" to 1, "B" to 2, "C" to 1)` to `mapOf(1 to listOf("A", "C"), 2 to listOf("B"))`
allan.conda
09/24/2020, 1:37 PMgroupBy
Joris PZ
09/24/2020, 1:43 PMlistOf("A" to 1, "B" to 2, "C" to 1).groupBy( { it.second}, { it.first})
Steven Wang
09/24/2020, 1:44 PM