Steven Wang
`listOf("A" to 1, "B" to 2, "C" to 1)` to `mapOf(1 to listOf("A", "C"), 2 to listOf("B"))`
allan.conda
groupBy
Joris PZ
listOf("A" to 1, "B" to 2, "C" to 1).groupBy( { it.second}, { it.first})
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