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# getting-started

[Slackbot]

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[diesieben07]

Function types, like generics, are erased. You can not check for () -> Int, you can only check for () -> Any?. To do that you use the normal is operator:
thing is () -> Any?

[Mark]

So thing is () -> Any? would return true for a class implementing () -> Int?

[diesieben07]

Yes, but it would also be true for a class implementing () -> String

[Mark]

Yes, of course. Thanks!

[diesieben07]

Note that this does not seem to work in JS, it only checks for any function