not sure how to make the list-to-be-added iterable so that it can be fed straight into addAll

oday

06/01/2020, 9:59 AM

not sure how to make the list-to-be-added iterable so that it can be fed straight into addAll

allan.conda

06/01/2020, 10:04 AM

it can be fed straight into addAll

You should be able to since addAll accepts Collection

mutableList.addAll(list2)

Matteo Mirk

06/01/2020, 10:17 AM

A list is already an Iterable:

List -▷ Collection -▷ Iterable

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