Is the only way to get the KClass of a List type (...

# getting-started

[bbaldino]

Is the only way to get the KClass of a List type (say, List<Int>) to do listOf<Int>().javaClass.kotlin? I get complaints trying to do List<Int>::class

[Milan Hruban]

these two give the same result

println(listOf<Int>().javaClass.kotlin)
println(listOf<Int>()::class)

[bbaldino]

Ah, good catch, that's a bit better. I was hoping there was a way to avoid creating an instance though

[Milan Hruban]

the generic type gets erased anyway right? Maybe you are just looking for List::class ?

[bbaldino]

That's actually what I'm playing with. In the KClass it's preserved

[bbaldino]

for example:

val INT_LIST_TYPE = listOf<Int>()::class
fun <T : Any> getterFor(valueType: KClass<T>) {
    // println(valueType.isSubclassOf(List::class))
    when (valueType) {
        Boolean::class -> println("boolean")
        INT_LIST_TYPE -> println("int list")
        else -> println("other")
    }
}

[bbaldino]

Hmmm, also problematic is that listOf<Int>()::class does not much KClass<List<Int>> . listOf gives KClass<out List<Int>> and List<Int> is expected to be just KClass<List<Int>>.

[bbaldino]

Another thing I came up with: `

inline fun <reified T : Any> getKClass(): KClass<T> = T::class

so I can then do getKClass<List<Int>>() and assign that to a variable to save

[bbaldino]

then they match