is there a way to convert a KFunction to a lambda ...

# getting-started

[bbaldino]

is there a way to convert a KFunction to a lambda other than just casting it?

[Ruckus]

This sounds like it may be a XY problem...

[bbaldino]

i've got a sort of factory function and want to return a constructor of a class--wanted to just use a reference to the constructor but felt the KFunction was overkill and just wanted to return a lambda

[bbaldino]

i decided to change it to have the factory do the instantiation and return the instance instead, but was still curious

[karelpeeters]

This just works:

class Foo
fun fooFactory(): () -> Foo = ::Foo

so I'm not sure i understand the question?

[bbaldino]

ah, yeah i had some generic/inheritance there that probably didn't make sense. it was like this:```interface Parent<T>
class Child : Parent<Boolean>
fun<T : Any> blah(): () -> Parent<T> = ::Child```

[SiebelsTim]

In that example T must be Boolean and cant be anything else.

[bbaldino]

yeah, realized after writing the simple example it was the type erasure issue. so guess doing fun<T : Any> blah(): () -> Parent<T> = ::Child as () -> Parent<T> fixes it

[marstran]

No, that will give a runtime time error if T is anything else than Boolean. Why do you even need T, when all you do is call the child constructor?

[marstran]

fun blah(): () -> Parent<Boolean> = ::Child

[marstran]

That is the only thing that works if you’re going to call the child constructor.

[bbaldino]

yeah, that was just for the purpose of a simplified example...in my code i had a longer block there that compared a reified type and then instantiated the right version and returned it, so i knew the implementation would always match T