``` data class User(val name: String, val email: S...

# getting-started

[sandi]

data class User(val name: String, val email: String)

val user: User get() = User(email = getEmail(), name = getName())

What is the order of execution here? Do named arguments get resolved (1) according to the data class argument positioning or (2) when creating the object with named arguments?

[Dominaezzz]

You might be able to see this in the bytecode.

[Luca Nicoletti]

I’d bet on (1) data class arguments’ positioning

[karelpeeters]

I'd bet (2) actually, but I'm not at a computer to test 😔

[sandi]

data class Test(val one: String, val two: String)

fun testFunc(): Test {
    return Test(two = getTwo(), one = getOne())
}

fun getOne(): String {
    return "Hello ${1}"
}

fun getTwo(): String {
    return "Hello ${2}"
}

decompiles to:

public final class TestKt {
   @NotNull
   public static final Test testFunc() {
      String var10002 = getTwo();
      String var0 = getOne();
      String var1 = var10002;
      return new Test(var0, var1);
   }

   @NotNull
   public static final String getOne() {
      return "Hello 1";
   }

   @NotNull
   public static final String getTwo() {
      return "Hello 2";
   }
}

Seems like it’s actually (2) @Luca Nicoletti, thanks for the tip @Dominaezzz!

[Luca Nicoletti]

return new Test(var0, var1);

[Luca Nicoletti]

var0 = getOne()

[Luca Nicoletti]

one is the first being passed to the constructor, even if you use named parameter, decompiled code re-order them

[sandi]

@Luca Nicoletti to clarify, I meant the order of execution of the functions getOne() and getTwo()

[Luca Nicoletti]

Oh, sorry, mis-understood then 🙂

[karelpeeters]

It would be pretty bad if they messed that up 😄

[sandi]

I agree, but it was not obvious from the docs 😄

[molikuner]

https://pl.kotl.in/rtLhUzrvd

Execution is in order of named arguments. Why look at bytecode 😄 ?