Is it possible to have a default argument for a fu...

# getting-started

[Ive Vasiljevic]

Is it possible to have a default argument for a function parameter (function having another function as a parameter and that function parameter has a default value just as a variable could have)?

[Ovsyannikov Alexey]

Hello. Yes, it is possible. For example, you will use somethings like:

fun doExample(exampleSubFun: (TypeOne, TypeTwo) -> Unit = {})

[Big Chungus]

fun test(block: () -> Unit = { println("default") }) {

}

[Ive Vasiljevic]

Okay. And how would I reference a number for example.

dip:(Int) -> Int = { TypedValue.applyDimension(TypedValue.COMPLEX_UNIT_DIP, [WHAT EVER INT NUM I SEND].toFloat(), resources.displayMetrics).toInt() }

Should I do dip:(nameOfTheVariable: Int) -> Int

[Big Chungus]

For single-arg functions use it

fun t(dip: (Int) -> Int = { TypedValue.applyDimension(TypedValue.COMPLEX_UNIT_DIP, it.toFloat(), resources.displayMetrics).toInt() }) {}

[Big Chungus]

Otherwise

fun t(dip: (Int,Int) -> Int = {int1,int2 -> TypedValue.applyDimension(TypedValue.COMPLEX_UNIT_DIP, int1.toFloat(), resources.displayMetrics).toInt() }) {}

[Ive Vasiljevic]

Thanks!