``` fun <F: Foo> foo1(fooRef: KProperty1<...

# getting-started

[Hullaballoonatic]

fun <F: Foo> foo1(fooRef: KProperty1<Bar, Foo>) = ...

fun <F: Foo> foo2(foo: Foo) = foo1(WHAT GOES HERE?)

Is there a simple way to do this? Bar::(something with foo)?

[karelpeeters]

foo1 takes a property of Bar with type Foo, and all you've got is an instance or Foo. How could that possibly converted to the latter?

[Hullaballoonatic]

so let's say fooRef: KProperty1<Bar, String>, e.g. Bar::name. How could you engineer KProperty1<Bar, String> from name?

[karelpeeters]

Do you happen to be confused about how variables work? If I have a class class Bar(val name: String) and then I do foo2(bar.name) there's no connection to bar anymore, bar.name is just an ordinary String instance out there with everything else

[karelpeeters]

You can't engineer a property from a random instance, it may not even be a property, foo("test"), it may be a "property" of multiple classes, it may be in a list somewhere, ...

[Hullaballoonatic]

Yeah, so you can provide the Bar part yourself again.

[Hullaballoonatic]

alright. i'll try to think of a different solution

[karelpeeters]

I don't get what you want to happen.