I know I could just omit the parameter but then I would have kotlinlang #getting-started

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Title

p

poohbar

10/17/2018, 12:25 PM

I know I could just omit the parameter but then I would have to do:

if (s == null) foo() else foo(s)

h

hudsonb

10/17/2018, 12:31 PM

Not sure default value helps you here, within

foo

you could

fun foo(input: String?)  {
    val s = input ?: "default"
}

Or maybe do both

fun foo(input: String? = "default")  {
    val s = input ?: "default"
}

a

arve

10/17/2018, 12:36 PM

fun foo(input: String? = "hello"): String {
            return input ?: "default"
        }

        assert(foo() == "hello")
        assert(foo(null) == "default")
        assert(foo("bar") == "bar")

This illustrates the behaviour you can expect

if you provide the same value as parameter default and null elvis fallback, you get the desired behaviour, as described in OP

that is,

fun foo(input: String? = "default"): String {
    return input ?: "default"
}

assert(foo() == "default")
assert(foo(null) == "default")
assert(foo("bar") == "bar")

p

poohbar

10/17/2018, 1:34 PM

thanks, that's pretty cumbersome tbh

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