I wonder why it get’s represented differently in a first place, given that both languages have vararg support that seems very similar =\

Ah, it’s more interesting that that, the case I mentioned above actually works ok. The case where I’m experiencing the problem is when I have vararg as a first argument and then a lambda as the second. In which case this behaviour kind of makes sense, given that there is no special last place lambda synthax or named parameters in java