Aregev2
08/06/2018, 4:15 PMShawn
08/06/2018, 4:18 PMlist.windowed(size = 2, step = 2)
.map { (a, b) -> a to b }
.toMap()
seems to achieve your goaladam-mcneilly
08/06/2018, 4:20 PMRuckus
08/06/2018, 4:46 PMmap
and toMap
steps with `associate`:
list.windowed(size = 2, step = 2)
.associate { (a, b) -> a to b }
Shawn
08/06/2018, 4:47 PMShawn
08/06/2018, 4:47 PMadam-mcneilly
08/06/2018, 5:02 PM