I have list1 that I need to associate to list2 one-to-one, is there an ideomatic way to do this?

# getting-started

[dave08]

I have list1 that I need to associate to list2 one-to-one, is there an ideomatic way to do this?

[spand]

zip()

[dave08]

Thanks!

[dave08]

What if I want specific indices of list2? So far I have: deviceSpecs.zip(listOf(1, 1, -1, 2, 4, 3, 0)) but then I need to use val elem2 = list2.getOrNull(it.second)....

[spand]

`map()`/`mapIndexed()` maybe ?

[dave08]

I guess zip is better in this case, since I need to generate test data, and anyways need to declare listOf(1, 1, -1, 2, 4, 3, 0)... it's not part of the fixtures, just the valid values...

[dave08]

But thanks anyways, I'll keep those in mind for other cases too!

[spand]

np