I don't think there's anythin in the collection ap...

# getting-started

[karelpeeters]

I don't think there's anythin in the collection apis that operates on reference equality.

[Daniel]

A huge thanks for your reply! Jep, must be referencial for this case

[brichards]

list1.filter { l1 -> list2.any{l1 === it} }

[brichards]

but this is an N^2 search would be better if you could some how make the search space in l2 smaller with each iteration