I want to do something like this: mylist.sort { it...

# getting-started

[Regan Russell]

I want to do something like this:
mylist.sort { it.popular or not } and then mylist.sort { it.name ascending } in the one list. I want the popular at the top and the rest sorted by name

[Sean Corfield]

A single sort with a comparator function that checks both popular and name sounds like the best option there I think.

[adam-mcneilly]

Scratch that it didn't work. Deleting.

[Sean Corfield]

What we often do when we're sorting across multiple "keys" is to synthesize a single thing to compare on. For something like this we'd prefix the name with a for popular items and z for not popular items and sort on that combined string.

[Sean Corfield]

(but do it all in the comparator)

[ilya.gorbunov]

sortWith(compareBy<YourItemType> { if (it.popular) 0 else 1 }.thenBy { it.name })

[Sean Corfield]

Oh very nice!

[Regan Russell]

Oh, I wish I'd used the ".thenBy" ... very nice... but its working and committed and pushed now