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<@U70GMFHEJ> there's no need to lose the node refe...
# getting-started
a
agomez
09/25/2017, 6:38 PM
@kristofdho
there's no need to lose the node reference
k
kristofdho
09/25/2017, 6:46 PM
by constructing pairs, but those are not needed and basically just overhead
a
agomez
09/25/2017, 6:51 PM
there's a lot of overhead before that in outgoing.toList(), and parseNode, getBtn(node)
agomez
09/25/2017, 6:51 PM
it's a question of finding the right balance between readibility, maintenabilty, and performance
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