<@U70GMFHEJ> there's no need to lose the node refe...
# getting-started
a
@kristofdho there's no need to lose the node reference
k
by constructing pairs, but those are not needed and basically just overhead
a
there's a lot of overhead before that in outgoing.toList(), and parseNode, getBtn(node)
it's a question of finding the right balance between readibility, maintenabilty, and performance