`data groupBy it 0 mapValues value gt value map it 1 ` kotlinlang #getting-started

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getting-started

Title

m

menegatti

08/16/2017, 9:53 AM

data.groupBy { it[0] }.mapValues { (_, value) -> value.map { it[1] } }

👍 2

t

tipsy

08/16/2017, 10:07 AM

thanks, this language (and the slack channel) never disappoints

k

karelpeeters

08/16/2017, 10:48 AM

Why not

data.groupBy { it[0] }.mapValues { (_, value) -> value[1]}

?

a

arekolek

08/16/2017, 10:52 AM

Why not

data.groupBy({ it[0] }, { it[1] })

? 😉

k

karelpeeters

08/16/2017, 10:56 AM

Even better.

t

tipsy

08/16/2017, 10:56 AM

nice

that's perfect @arekolek, thanks

👍 1

i need the value to be an

Array<String>

rather than a

List<String>

though, where do i put that with this approach? 🤔

k

kirillrakhman

08/16/2017, 11:11 AM

put

.toTypedArray()

at the end of the call

a

arekolek

08/16/2017, 11:11 AM

I guess that would be

data.groupBy({ it[0] }, { it[1] }).mapValues { it.value.toList() }

t

tipsy

08/16/2017, 11:14 AM

still more readable i think

return data.groupBy(
    { it[0] },
    { it[1] }
).mapValues { it.value.toTypedArray() }

a

arekolek

08/16/2017, 11:16 AM

I read that wrong, I thought you needed a list, which it already was 😛

t

tipsy

08/16/2017, 11:17 AM

i wish i needed a list 😄

m

menegatti

08/16/2017, 11:43 AM

@arekolek nice one, I didn't know

groupBy

took more than one lambda

3 Views

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