Why doesn't `Regex` override `equals` ?

# stdlib

[Mikhail]

Why doesn't Regex override equals ?

[Mikhail]

I know I can like compare them by using the pattern property but would be more convenient to not do so.

[Mikhail]

image.png

[ephemient]

that's not correct: it'll falsely "a".toRegex() == "a".toRegex(RegexOption.IGNORE_CASE) as well as falsely "a".toRegex() != "(?:a)".toRegex(). since there's no good way to determine structural equivalence, it isn't attempted

[ephemient]

also of note: on JVM and JS, Kotlin's Regex is just a wrapper around the native Pattern or RegExp, neither of which support structural equality

[Mikhail]

Oh I got it now
Thank you for a good explanation

[ilya.gorbunov]

We're considering doing that in this issue https://youtrack.jetbrains.com/issue/KT-23521/Regex-should-implement-structural-equality

[todd.ginsberg]

I think this is the first time I’ve read a thread on here that ephemient has participated in where they aren’t the one to link to the most relevant YT issue. 🙂