Is there any reason why `Sequence<T>.drop(n:...

# stdlib

[Junjie Wu]

Is there any reason why Sequence<T>.drop(n: Int) param type is Int instead of Long ? I thought Kotlin’s sequence is equivalent to Java’s stream, and presuming the type should be the same as Stream<T> skip(long n);

[Junjie Wu]

In what aspect? From my understanding, they are all representing a possible infinite stream of data, and can do minimal & lazy calculations

[Junjie Wu]

Thanks for your explanation, but back to the question, I still get confused why it's an Int but not a Long, since it can represent an infinite flow

[Junjie Wu]

yeah, this makes sense. I just wonders if there’s some special thinkings behind when implementing this function

[ephemient]

Sequence effectively wraps an Iterator, Stream effectively wraps a Spliterator, these are not the same

[ephemient]

in particular, collections are expected to be representable in-memory and thus are explicitly limited to int sizes, which extends through iterators and sequences, while spliterators are generalized to larger and parallel streams